from app.models import db, Period, Project, Category

# TODO: make this configurable, and choose another place to use it,
#       in 'routes.py' maybe
# Charge as stored on a 100% basis, percent of total worked time;
# Here it is possible to convert to an ETP basis, dividing by 100
# or we set it to '1' if we want to keep the percent basis
charge_unit = 100

def projects():
    """

    Build the list of all projects, with their charges for the current period

    Returns a table with headers in the first line:
    Id, Project name, Category_1, ... , Category_n, Total_Charge_for_the_period

    The category cells embed the list of the labels of the project for that category.

    :return:
    """

    current_period_id = get_current_period()

    sql_txt = """

            select p.id, IFNULL(sum(tc.charge_rate), 0) as total_charge

            from project as p left join

               ( select c.project_id, c.charge_rate from charge c where c.period_id = {})

            tc
            on p.id = tc.project_id
            group by p.id
            order by total_charge desc;

            """.format(current_period_id)

    projects_charges = db.session.execute(sql_txt).fetchall()
    # First row is table titles
    all_projects = [["Id", "Projet"]]

    # Add all categories as next table titles

    # headers will then look like [["Id", "Projet", "Domaine", "Pôle"]]

    categories = Category.query.all()
    for c in categories:

        all_projects[0].append(c.name)

    # then add charge title
    # headers become [["Id", "Projet", "Domaine", "Pôle", "Charge"]]

    all_projects[0].append("Charge")
    # Build the table row by row

    for _pc in projects_charges:
        p_id = _pc[0]

        project = Project.query.get(int(p_id))

        # adding 2 first columns: id, name

        project_row = [project.id, project.name]

        # then labels, many for each category
        for category in categories:

            # we build the labels.name list of the intersection of current category's labels with project's labels
            # Comprehensive shortcut is:
            # labels = [_cl.label.name for _cl in category.labels if _cl.label in [_pl.label for _pl in project.labels]]
            #
            category_labels = [_cl.label for _cl in category.labels]
            project_labels = [_pl.label for _pl in project.labels]
            intersection_labels = list(set.intersection(set(project_labels), set(category_labels)))
            labels = [label.name for label in intersection_labels]

            project_row.append(labels)
        # then add total charge
        project_row.append(_pc[1])

        all_projects.append(project_row)

    return all_projects

def agents():

    """

    Build the list of all agents, with their charges for the current period

    :return:
    """

    current_period_id = get_current_period()

    sql_txt = """

            select a.id, a.firstname, a.secondname, IFNULL (sum(tc.charge_rate), 0) as total_charge

            from agent as a left join

               ( select c.agent_id, c.charge_rate from charge c where c.period_id = {})

            tc
            on a.id = tc.agent_id
            group by a.id
            order by total_charge desc;

            """.format(current_period_id)

    all_agents = db.session.execute(sql_txt).fetchall()

    return all_agents

def charges_by_project(project_id):
    """
    Build the flatten list of charges for one project, period by period
    :param project_id:
    :return:
    """

    req_sql = f"""
            select p.name as period_name,
                   a.firstname ||" "|| a.secondname as agent_name,
                   s.name as service_name,
                   c2.name as capacity_name,
                   c.charge_rate as charge_rate
            from charge as c
                     join period p on c.period_id = p.id
                     join project p2 on c.project_id = p2.id
                     join service s on c.service_id = s.id
                     join agent a on a.id = c.agent_id
                     join capacity c2 on c2.id = c.capacity_id
            where project_id = {project_id}
            order by c.period_id
            """

    req_res = db.session.execute(req_sql)
    results = list(req_res)
    # Remove comma
    nocomma_results = []
    for line in results:
        nocomma_line = [str(cell) for cell in line]
        nocomma_results.append(nocomma_line)

    headers = ["Periode", "Agent", "Service", "Fonction", "Charge"]

    nocomma_results.insert(0, headers)
    return nocomma_results

def charges_by_project_stacked(project_id, category="service"):
    """
    Build the list of charges for one project, period by period
    :param project_id: the project's id we want to return data for
    :param category: what dict to build for each period, 'service' or 'capacity' ?
    :return: a 2 dim table with header as first line and datas next, of the form
            period, category_0, category_1, ....., category_n,

            per_0, value_00, value_01, ....., value_0n,
            per_1, value_10, value_11, ....., value_1n,

                .
                .

            per_n, value_n0, value_n1, ....., value_nn,

    TODO: common with charges_by_agent_stacked(agent_id): code to extrat

    """

    if category == 'capacity':

        category_table = 'capacity'

        sql_req = """

        select sum(c.charge_rate)

        from capacity c1 left join
            charge c on c1.id = c.capacity_id and project_id = {} and period_id={}

            group by c1.id

        order by c1.id
        """

    elif category == 'service':

        category_table = 'service'

        sql_req = """

        select sum(c.charge_rate)

        from service s left join
            charge c on s.id = c.service_id and project_id = {} and period_id={}

            group by s.id

        order by s.id
        """
    else:
        raise ValueError("Waiting for 'service' or 'capacity'")

    categories_req = "select name from {} order by id".format(category_table)

    categories = [c for (c,) in db.session.execute(categories_req)]

    headers = ['period'] + categories

    all_charges = [headers]
    for (period_id, period_name) in db.session.execute("select id, name from period order by id"):
        # build the request from the string previously set
        charge_by_categorie_req = sql_req.format(project_id, period_id)
        # build the charges line for the current period
        category_charges = [period_name]
        for (category_rate,) in db.session.execute(charge_by_categorie_req):

            category_rate = str(round(category_rate / charge_unit, 2)) if category_rate else '0'

            category_charges.append(category_rate)
        all_charges.append(category_charges)

    return all_charges

def charges_by_agent_stacked(agent_id):
    """
    Build the list of charges for all projects of one agent, period by period

    TODO: common with charges_by_project_stacked(project_id, ..) code to extrat

    :param agent_id:
    :return:
    """
    categories_req = "select name from project order by id"
    categories = [c for (c,) in db.session.execute(categories_req)]
    headers = ['period'] + categories
    all_charges = [headers]
    for (period_id, period_name) in db.session.execute("select id, name from period order by id"):
        charge_by_project_req = """
                               select sum(c.charge_rate)
                                from project p
                                         left join
                                     charge c on p.id = c.project_id and agent_id = {} and period_id = {}
                                group by p.id
                                order by p.id 
                            """.format(agent_id, period_id)

        category_charges = [period_name]
        for (category_rate,) in db.session.execute(charge_by_project_req):

            category_rate = str(round(category_rate / charge_unit, 2)) if category_rate else '0'

            category_charges.append(category_rate)
        all_charges.append(category_charges)
    return all_charges

def charges_by_agent_tabled(agent_id):
    """
    Build the flatten list of charges for one agent, period by period
    :param agent_id:
    :return:
    """
    req_sql = f"""
            select p.name as period_name,
                   p2.name as project_name,
                   s.name as service_name,
                   c2.name as capacity_name,
                   c.charge_rate as charge_rate
            from charge as c
                     join period p on c.period_id = p.id
                     join project p2 on c.project_id = p2.id
                     join service s on c.service_id = s.id
                     join agent a on a.id = c.agent_id
                     join capacity c2 on c2.id = c.capacity_id
            where agent_id = {agent_id}
            order by c.period_id
            """
    req_res = db.session.execute(req_sql)
    results = list(req_res)
    # Remove comma
    nocomma_results = []
    for line in results:

        nocomma_line = [str(cell) for cell in line]

        nocomma_results.append(nocomma_line)

    headers = ["Periode", "Projet", "Service", "Fonction", "Charge"]

    nocomma_results.insert(0, headers)
    return nocomma_results

def charges_by_agent(agent_id):

    periods = db.session.execute("select name from period")
    sql_txt = "select p.name, sum(charge_rate)  from charge inner join period p on charge.period_id = p.id\

                where agent_id={} group by period_id order by p.name" \
        .format(agent_id)

    request = db.session.execute(sql_txt)

    all_charges = []
    charges_list = [(period, charge) for (period, charge) in request.fetchall()]
    charges_dict = dict(charges_list)
    for (p,) in periods:
        if p in charges_dict.keys():
            all_charges.append([p, charges_dict[p]])
        else:
            all_charges.append([p, 0])

    return all_charges

def get_current_period():
    """
    :return:  the id of the period of current day
    """
    # TODO: request on dates as soon as periods are dated

    p = Period.query.filter((Period.name == '2021') | (Period.name == '2021_S1')).one()
    return p.id